8y^2-3y=120

Solution for 8y^2-3y=120 equation:

8y^2-3y=120

We move all terms to the left:

8y^2-3y-(120)=0

a = 8; b = -3; c = -120;
Δ = b2-4ac
Δ = -32-4·8·(-120)
Δ = 3849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{3849}}{2*8}=\frac{3-\sqrt{3849}}{16}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{3849}}{2*8}=\frac{3+\sqrt{3849}}{16}
$